Example to check whether an integer is a prime number or not using for loop and if…else statement. If the number is not prime, it’s explained in output why it is not a prime number.

A positive integer greater than 1 which has no other factors except 1 and the number itself is called a prime number. 2, 3, 5, 7 etc. are prime numbers as they do not have any other factors. But 6 is not prime (it is composite) since, `2 x 3 = 6`

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## Source Code

```
# Program to check if a number is prime or not
num = 407
# To take input from the user
#num = int(input("Enter a number: "))
# prime numbers are greater than 1
if num > 1:
# check for factors
for i in range(2,num):
if (num % i) == 0:
print(num,"is not a prime number")
print(i,"times",num//i,"is",num)
break
else:
print(num,"is a prime number")
# if input number is less than
# or equal to 1, it is not prime
else:
print(num,"is not a prime number")
```

**Output**

407 is not a prime number 11 times 37 is 407

In this program, variable num is checked if it’s prime or not. Numbers less than or equal to 1 are not prime numbers. Hence, we only proceed if the `num` is greater than 1.

We check if `num` is exactly divisible by any number from 2 to num – 1. If we find a factor in that range, the number is not prime. Else the number is prime.

We can decrease the range of numbers where we look for factors.

In the above program, our search range is from 2 to `num - 1`

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We could have used the range, `range(2,num//2)`

or `range(2,math.floor(math.sqrt(num)))`

. The latter range is based on the fact that a composite number must have a factor less than the square root of that number. Otherwise, the number is prime.

You can change the value of variable `num` in the above source code to check whether a number is prime or not for other integers.

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